Print all odd
integers from the interval [a, b] in ascending order.
Input. Two integers a
and b (a < b).
Output. Print all odd
integers from the interval [a, b] in ascending order on a single
line.
|
Sample input |
Sample output |
|
2 7 |
3 5 7 |
loop
Algorithm analysis
Use a for loop. Iterate through all numbers from a to b in
ascending order and print only the
odd ones.
Algorithm implementation
Read the input data.
scanf("%d %d", &a, &b);
Iterate
through all numbers from a to b in ascending order and print only the odd ones.
for (i = a; i <= b; i++)
if (i % 2 == 1)
printf("%d ", i);
Java implementation
import java.util.*;
class Main
{
public static void main(String[] args)
{
Scanner con = new Scanner(System.in);
int a = con.nextInt();
int b = con.nextInt();
for(int i = a; i <= b; i++)
if (i % 2 == 1)
System.out.print(i + " ");
con.close();
}
}
Python implementation
Read the input data.
a, b = map(int, input().split())
Iterate
through all numbers from a to b in ascending order and print only the odd ones.
for i in range(a, b + 1):
if i % 2 == 1: print(i, end=" ")
Python implementation – list
Read the input data.
a, b = map(int, input().split())
Create a
list containing all the odd numbers from the interval [a, b].
res = [x for x in
range(a, b + 1) if x % 2 != 0]
Print the answer.
print(*res)